6x.(x+2016) - (x+2016) = 0
=> (6x -1) (x +2016) =0
=> 2 trường hợp
trường hợp 1 : 6x-1 = 0
=> x = 1/6
trường hợp 2 : x +2016 =0
=> x = - 2016
=> x € {1/6;-2016}
\(6x\left(x+2016\right)-x-2016=0\)
\(6x\left(x+2016\right)-\left(x+2016\right)=0\)
\(\left(x+2016\right)\left(6x-1\right)=0\)
=> \(x+2016=0\)hoặc \(6x-1=0\)
Với \(x+2016=0\)=>\(x=-2016\)
Với \(6x-1=0\)=>\(6x=1\)=>\(x=\frac{1}{6}\)
Vậy \(x=-2016;x=\frac{1}{4}\)
Ta có \(6x.\left(x+2016\right)-x-2016=0\)
\(\Rightarrow6x.\left(x+2016\right)-\left(x+2016\right)=0\)
\(\Rightarrow\left(x+2016\right).\left(1+6x\right)=0\)
\(\Rightarrow\hept{\begin{cases}2016+x=0\\1+6x=0\end{cases}\Rightarrow}\hept{\begin{cases}x=-2016\\6x=-1\Rightarrow x=-\frac{1}{6}\end{cases}}\)
Vậy \(x\in\left\{-2016;-\frac{1}{6}\right\}\)
Mình nhầm 6x-1=0 =>6x=1=>x=\(\frac{1}{6}\)
