32x-1=243
Mà 243=35
=>2x-1=5
=>2x=5+1
=>2x=6
=>x=6:2
=>x=3
\(3^{2x-1}=243=3^5\)
\(\Rightarrow2x-1=5\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
\(3^{2x-1}=243\)
\(3^{2x-1}=3^5\)
\(\Rightarrow2x-1=5\)
\(2x=6\)
\(x=3\)
Ta có: \(3^{2x-1}=243=>3^{2x-1}=3^3=>2x-1=3=>2x=4\)
=> x=2
Vậy...