`|-2x+1/8|=|1/2-1/3|`
`|-2x+1/8|=|(-1)/6|`
`| -2x + 1/8| = 1/6`
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{1}{8}=\dfrac{1}{6}\\-2x+\dfrac{1}{8}=\dfrac{1}{6}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{1}{6}+\dfrac{1}{8}\\-2x=\dfrac{1}{6}-\dfrac{1}{8}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{24}\\-2x=\dfrac{1}{24}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{24}:2\\x=\dfrac{1}{24}:\left(-2\right)\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{24}.\dfrac{1}{2}\\x=\dfrac{1}{24}.\dfrac{-1}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{48}\\x=-\dfrac{1}{48}\end{matrix}\right.\)
Vậy.....
`#BaoL i n h`
`|-2x+1/8|=|1/2-1/3|`
`| -2x + 1/8| = 1/6`
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{1}{8}=\dfrac{1}{6}\\-2x+\dfrac{1}{8}=\dfrac{1}{6}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{1}{6}+\dfrac{1}{8}\\-2x=\dfrac{1}{6}-\dfrac{1}{8}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{24}\\-2x=\dfrac{1}{24}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{24}:2\\x=\dfrac{1}{24}:\left(-2\right)\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{48}\\x=-\dfrac{1}{48}\end{matrix}\right.\)
`#LeMichael`