(2x+1)+(2x+2)+..................+(2x+2015)=0
<=>2x+1+2x+2+.................+2x+2015=0
<=>(2x+2x+2x+....+2x)+(1+2+3+4+5+.......+2015)=0
l^l^lcó 2015 sốl^l^l
<=>4030x+2031120=0<=>x=-504
Vậy x=-504
Tìm x : (2x + 1) + (2x + 2) + (2x + 3) + ... + (2x + 2015) = 0
tìm x :(2x+1)+(2x+2)+...+(2x+2015)=0
Tìm x: (2x+1)+(2x+2)+...+(2x+2015) = 0
(2x+1)+(2x+2)+...+(2x+2015)=0.Tìm x
tìm x biết (2x+1)+(2x+2)+.....+(2x+2015)=0
TÌm x biết : (2x + 1 ) + ( 2x + 2 ) + ..... + ( 2x + 2015 ) = 0
Tìm x biết (2x+1)+(2x+2)+...+(2x+2015)=0
tìm x biết ( 2x+1) + ( 2x+2 ) +......( 2x+2015) =0
tìm x biết (2x+1)+(2x+2)+.....+(2x+2015)=0
