tìm x :1+3+5+...+(2x+1)=2601
cứu mk vs :
tìm x :
1+3+5+...+(2x+1)=2601
cứu vs !!!!!!!!!!!!!!1
TÌM X BIẾT :
1+3+5+...+(2x+1)=2601
ai nhanh mk tk !!!!!!!!!!!!! giúp mk nha!
HEPL MEEE!!
Tìm x
1 + 3 + 5 + ... + '' 2x + 1 ''\(=\) 2601
Các bạn giúp mình nhé
tìm số tữ nhiên x thỏa mãn :
1+3+5+.....+x=2601
B1: Tìm x:
1/ \(\dfrac{x+3}{15}\) = \(\dfrac{1}{3}\) - \(\dfrac{1}{15}\)
2/ (2x - 5) = (x - 3) = 0
3/ (3x - 4) - (2x - 5) = 3
4/ (2x + 1) x (\(\dfrac{1}{2}\)x - 1) = 0
Tìm x bt 2x/ 1 × 3 + 2x/ 3 x 5 + 2x / 5 x 7 +...+2x/2011×2013
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0