\(\left(1-\frac{3}{10}-x\right):\left(\frac{19}{10}-1-\frac{2}{5}\right)+\frac{4}{5}=1\)
\(\Rightarrow\left(\frac{7}{10}-x\right):\frac{1}{2}=\frac{1}{5}\\ \frac{7}{10}-x=\frac{1}{5}.\frac{1}{2}\\ \frac{7}{10}-x=\frac{1}{10}\\ \Rightarrow x=\frac{7}{10}-\frac{1}{10}=\frac{3}{5}\)