\(\Rightarrow\dfrac{1}{3}x+\dfrac{5}{3}x+1x=\dfrac{-5}{7}\\ x\cdot\left(\dfrac{1}{3}+\dfrac{5}{3}+1\right)=\dfrac{-5}{7}\\ x\cdot3=\dfrac{-5}{7}\\ x=\dfrac{-5}{21}\)
\(\dfrac{1}{3}x+\dfrac{5}{3}x+x=-\dfrac{5}{7}\)
\(\left(\dfrac{1}{3}+\dfrac{5}{3}+1\right)x=-\dfrac{5}{7}\)
\(\left(\dfrac{1}{3}+\dfrac{5}{3}+\dfrac{3}{3}\right)x=-\dfrac{5}{7}\)
\(3x=-\dfrac{5}{7}\)
\(\Rightarrow x=-\dfrac{5}{7}:3\)
\(\Rightarrow x=-\dfrac{5}{7}.\dfrac{1}{3}\)
\(\Rightarrow x=-\dfrac{5}{21}\)