Question

Tìm x: (1-2x)^2 = (2x-5) . (2x-1)
mn giúp mik vs ạ ;-;

Answer 1

\(\left(1-2x\right)^2=\left(2x-5\right)\left(2x-1\right)\\ < =>1^2-2.1.2x+\left(2x\right)^2=4x^2-10x-2x+5\\ < =>1-4x+4x^2=4x^2-12x+5\\ < =>4x^2-4x^2+12x-4x=5-1\\ < =>8x=4\\ < =>x=\dfrac{1}{2}=>S=\left\{\dfrac{1}{2}\right\}\)

Answer 2

\(\left(1-2x\right)^2=\left(2x-5\right)\left(2x-1\right)\)

\(1-4x+4x^2=4x^2-12x+5\)

   \(-4x+4x^2=4x^2-12x+4\)

                \(8x=4\)

                  \(x=4:8\)

                  \(x=\dfrac{1}{2}.\)

\(Vậy...\)