x.(y+3)=0
=>y+3=0
=>y=-3
hoặc
=>x=0
Vậy A {0;-3}
x.(y+3)=0
=>y+3=0
=>y=-3
hoặc
=>x=0
Vậy A {0;-3}
Biet diem O,A thuoc do thi ham so y=1/2x .Tim toa do M(2,m) de 3 diem O,A,M thang hang
a,ve do thi cac ham so y=\(\frac{-3}{2}\)x va y=\(\frac{2}{3}\)x tren cung 1 he truc toa do
b,tren do thi ham so y=\(\frac{-3}{2}\)x lay diem A co hoanh do la 2.tren do thi ham so y=\(\frac{2}{3}\)x.Lay diem C co hoanh do la 3.do goc AOC,sau do bieu dien diem B tren mat phang toa do sao cho OABC la hinh vuong
Bai 1;
Ve tren mat phang toa do Oxy cac diem A;B va C.Tinh dien tich cua tam giac ABC biet :
+Diem A co toa do A(x0;y0) ma x0 +1 =0 va y0-2=0
+diem B co toa do B(x1;y1) ma (x1-2)^2+(y1+3)^2=0
+Diem C co toa do C(x2;y2) ma /x2-4/+can y2-3=0
a,ve do thi ham so y=-1,5x
b,biet rang diem M(a,-3) thuoc do thi ham so tren .Tim gia tri cua a
Cho ham so y=f(x)=-2x
a, Ve do thi ham so tren mat phang toa do Oxy
b,Tim a biet f(a-4)=6
cho hai ham so y=f(x)=|2x| va y=g(x)=3
a)ve tren cung mot he truc toa do Oxy do thi cua hai ham so do
b)dung do thi ham so tim cac gia tri cua x sao cho |2x|<3
choham so y = ax
a ) xac dinh he so a biet do thi cua ham so di qua A ( 2;3)
b ) ve do thi cua ham so voi a vua tim duoc
c) diem M ( 1005,2010) co thuoc do thi ham so vua tim duoc o tren khong ? Vi sao
cho ham so y=-2*x
danh dau diem M tren do thi biet diem M co hoanh do bang 2.Tinh tung do
Cho ham so y = (m-1)x
A. Tim m de do thi ham so tren di qua diem M(-1;2)
B.Voi m tim duoc o cau a. Viet cong thuc ham so tren va ve do thi ham so