\(xy+1=x+y\)
\(\Leftrightarrow xy-x-y+1=0\)
\(\Leftrightarrow x\left(y-1\right)-\left(y-1\right)\)
\(\Leftrightarrow\left(x-1\right)\left(y-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\y-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\y=1\end{cases}}}\)
Vậy \(x=1;y=1\)
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