Question

tìm tất cả các cặp số nguyên x,y,z thỏa mãn x²+4y²+z²<2xy+2y-2z

Answer 1

Do \(x,y,z\inℤ\)

nen tu gia thiet suy ra

\(x^2+4y^2+z^2-2xy-2y+2z\le-1\)

\(\Leftrightarrow\left(x-y\right)^2+\left(z+1\right)^2+\left(y-1\right)^2+2y^2\le1\)

mat khac

\(\hept{\begin{cases}\left(y-1\right)^2+2y^2>0\\\left(x-y\right)^2+\left(z+1\right)^2\ge0\end{cases}}\)

nen \(\left(x-y\right)^2+\left(z+1\right)^2+\left(y-1\right)^2+2y^2=1\)

den day ban lap bang cac gia tri se tim duoc \(\left(x,y,z\right)=\left(0,0,-1\right)\)