tim n la stn de p=(x-1)(x^2-x+1) la snt
Tim stn n de n+1 va n-3 la 2 snt cung nhau
Cho n la STN , tim SNT P co 2cs sao cho: P= UCLN[2n-3; 3n+15]
MK can gap
tìm snt 3 c/s, nếu viết ng lại la lập phương 1 STN
tim n la stn de p=(x-1)(x^2-x+1) la 1 so nguyen to
tim SNT p sao cho 2.p2 -3 va 2.p2 +3 la cac SNT
Tim SNT ( so nguyen to ) P DE:
a) p + 2, p+ 94 cungx la SNT
b) p+6,p+8,p+12,p+14 cungx la SNT
tim x;y (la STN) biet(x-2).(2y-3)=26
cho 2 STN co hieu la 4 . neu nhan 1 so len 3 lan va giu nguyen so kia ta co hieu la 60 . tim 2 STN