Question

Tìm số Z x, biết :

(8+x).(6-x)=0

Answer 1

\(\left(8+x\right)\left(6-x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}8+x=0\\6-x=0\end{matrix}\right.\)                  \(\Rightarrow\left[{}\begin{matrix}x=-8\\x=6\end{matrix}\right.\)

            Vậy \(x\in\left\{-8;6\right\}\)

Answer 2

\(\left(8+x\right).\left(6-x\right)=0\)

\(=>8+x=0\) hoặc \(6-x=0\)

Nếu \(8+x=0\) \(=>x=-8\)

Nếu \(6-x=0=>x=6\)

Vậy \(x\in\left\{-8;6\right\}\)