a) 219 - 7 (x + 1) = 100
7 ( x + 1)= 219 -100
7 ( x+ 1) =119
x+1=119 : 7
x+1=17
x=17-1
x= 16
a) 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
=> x = 16
b)(3x-6).3 = 3^4
(3x-6).3 = 81
3x-6= 81:3
3x-6= 27
3x = 27-6
3x=21
=> x= 7.
kik nha
(3x - 6) . 3 = \(3^4\)
(3x-6) = \(3^4-3\)
( 3x-6) =\(3^3\)
3x-6=27
3x = 27 +6
3x = 33
x = 33:3
x=11
a) 219 - 7 ( x+1 ) = 100 b) (3x - 6) . 3 = 34
7( x+1 ) = 219 -100 3x - 6 = 34 : 3
7(x+1) = 119 3x - 6 = 81 : 3
x+1 = 119 : 7 3x - 6 = 27
x+1 = 17 3x = 27 + 6
x = 17 - 1 3x = 33
x = 16 x = 33 : 3
x = 11
7 (x + 1) = 219 - 100
7 (x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
(3x - 6) . 3 = 34
(3x - 6) . 3 = 81
3x - 6 = 81 : 3
3x - 6 = 27
3x = 27 + 6
3x = 33
x = 33 : 3
x = 11
Đúng ko
a) 7(x+1) = 219-100 b) 3x-6=3 mũ 4 nhân 3
7(x+1)=119 3x-6=3 mũ 5
x+1=119:7 3x-6=243
x+1=17 3x=243+6
x =17-1 3x=249
x =16 x=249:3
x=83
nhá
7(x-1)=219-100
7(x-1)=119
x-1=119:7
x-1=17
x=17+1
x=18