Ta có x^35=x^45
<=>x^45-x^35=0
<=>x^35.(x^10-1)=0
<=> \(\orbr{\begin{cases}x^{35}=0\\x^{10}-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x^{10}=1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\\orbr{\begin{cases}x=1\\x=-1\end{cases}}\end{cases}}}\)
\(x^{35}=x^{45}\)
=>\(x^{45}-x^{35}=0\)
=>\(x^{35}.\left(x^{10}-1\right)=0\)
=>\(x^{35}=0\) hoặc \(x^{10}-1=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{10}-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1;x=-1\end{cases}}\)
Vậy \(x=0;x=1;x=-1\)