Question

Tim so tu nhien x biet rang:

a/  8.6+288:(X-3)²=50

b/ (x² - (6²-(8²-9.7)³- 7.5)³- 5.3)³= 1        giup minh voi nhe

Answer 1

a/  8.6+288:(X-3)²=50

48+288:(x-3)²=50

288:(x-3)²=50-48=2

(x-3)²=288:2=144

(x-3)²=12²

x-3=12

x=12+3=15

b/ (x² - (6²-(8²-9.7)²- 5.3)³= 1

(x² - (6²-(64-9.7)²- 5.3)³= 1

(x² - (6²-(64-63)²- 5.3)³= 1

(x² - (6²-1²- 5.3)³= 1

(x² - (36-1- 15)³= 1

x² - 20³= 1

x² - 8000= 1

x²=1+8000=8001

x²=................(de sai

Answer 2

b) 

{ x² - [ 6² - ( 8² - 9.7)³ - 7.5]³ - 5.3 }³ = 1

{ x² + [ 36 - (64 - 63)³ - 35]³ - 15}³ = 1

[ x² - ( 36 - 1³ - 35 ) - 15 ]³ = 1

[ x² - ( 36 - 1 - 35 ) - 15]³ = 1

[ x² - ( 35 - 35 ) - 15]³ = 1

[ x² - 0 - 15]³ = 1

( x² - 15 )³ = 1

<=> ( x² - 15)³ = 1³

=> x² - 15 = 1

<=> x² = 16

=> x = 4