Question

Tìm  số tự nhiên x, biết 

219 -7 .(x+1) = 5^2 .2^2

 

Answer 1

219 -7 .(x+1) = 5^2 .2^2 => x = 16

Answer 2

x=(219-5^2.2^2)/7-1=16

Answer 3

219 - 7 . (x+1) =5^2 . 2^2

219 - 7 . (x+1)=25.4

219-7.(x+1)=100

      7.(x+1)=219-100

      7.(x+1)=119

        x+1  = 119:7

        x+1 = 17

        x     =17-1

        x     =16

Vay x =16

Answer 4

h cho minh nha

Answer 5

219-7.(x+1)=5^2.2^2

219-7.(x+1)=100

7.(x+1)=219-100

7.(x+1)=119

x+1=119/7

x+1=17

x=17-1

x=16

Answer 6

219-7.(x+1)=100 =>7.(x+1)=219-100=119=>119:7=17=x+1=>x=17-1=16

Answer 7

219-7.(x+1)=5².2²

219-7.(x+1)=25.4

219-7.(x+1)=100

7.(x+1)=219-100

7.(x+1)=119

x+1=119:7

x+1=17

x=17-1

x=16

Vay x=16