tìm so tu nhien x biet (1/1.2.3 + 1/2.3.4+...+ 1/8.9.10).x=23/45
tim so tu nhien x biet (1/1.2.3+1/2.3.4+...+1/8.9.10)x=22/45
Tim so tu nhien x biet (1/1.2.3+1/2.3.4+...1/8.9.10)x=22/45
tim so tu nhien x biet (1/1.2.3+1/2.3.4+...+1/8.9.10)x=22/45
Tim x biet
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)
Tim x biet: \(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...\frac{1}{8.9.10}\right)x=\frac{22}{45}\)
(1/1.2.3+1/2.3.4+...+1/8.9.10).x=23/45
(\(\dfrac{1}{1.2.3}\)+\(\dfrac{1}{2.3.4}\)+...+\(\dfrac{1}{8.9.10}\)).x=\(\dfrac{23}{45}\)
tìm x biết
(1/1.2.3+1/2.3.4+1/3.4.5+...+1/8.9.10)x=23/45