a) 32 < 2n < 128
25 < 2n < 27
=> 2n = 26
=> n = 6
Vậy n = 6
b) 9 . 27 \(\le\) 3n \(\le\)243
=> 243 \(\le\)3n \(\le\)243
=> 35 \(\le\)3n \(\le\)35
=> 3n = 35
=> n = 5
Vậy n = 5
Ủng hộ mk nha !!! ^_^
) 32 < 2n < 128
25 < 2n < 27
=> 2n = 26
=> n = 6
Vậy n = 6
b) 9 . 27 $\le$≤ 3n $\le$≤243
=> 243 $\le$≤3n $\le$≤243
=> 35 $\le$≤3n $\le$≤35
=> 3n = 35
=> n = 5
Vậy n = 5
\(a,32< 2^n< 128\)
\(2^5< 2^n< 2^7\)
\(\Rightarrow2^n< 2^6\)
\(\Rightarrow n=6\)
vậy \(n=6\)
\(b,9.27\le3^n\le243\)
\(3^9\le3^n\le3^5\)
\(\Rightarrow3^n=3^5\)
\(\Rightarrow n=5\)
vậy \(n=5\)
Tìm số rự nhiên biết :
a) 32 < 2^n < 128
<=> 2^5 < 2^n < 2^7
=> 5 < n < 7
<=> 5 < 6 < 7
=> n = 6
Vậy n = 6
a)32<2^n<128
2^5<2^n<2^7
=>5<x<7
=>x=6
b)9.27_<3^n_<243
243_<3^n_<243
3^5_<3^n_<3^5
=>5_<n_<5
=>n=5
