\(\left(2n-1\right)^4:\left(2n-1\right)=27\)
\(\left(2n-1\right)^3=3^3\)
\(\Rightarrow2n-1=3\)
\(\Rightarrow2n=3+1\)
\(\Rightarrow2n=4\)
\(\Rightarrow n=4:2\)
\(\Rightarrow n=2\)
(2n - 1)4 : (2n - 1)= 27.
(2n-1)3=27
(2n-1)3=33
=>2n-1=3
2n=4
x=2
Vậy n=2