Vì 2a + 7 \(⋮\) a + 2 <=> 2(a + 2) + 3 \(⋮\) a + 2
=> 3 \(⋮\) a + 2 (vì 2(a + 2) \(⋮\) a + 2)
=> a + 2 \(\in\) Ư(3) = {1; 3}
a + 2 = 1 => a = -1 (loại)
a + 2 = 3 => a = 1 (chọn)
Vậy a = 1
\(2a+7⋮a+2\)
\(\Rightarrow2a+4+3⋮a+2\)
\(\Rightarrow2\left(a+2\right)+3⋮a+2\)
mà \(2\left(a+2\right)⋮a+2\Rightarrow3⋮a+2\)
\(\Rightarrow a+2\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
\(\Rightarrow a\in\left\{1\right\}\)
Đáp án là 1 nha