Tìm x , y \(\in Z\)biết :
a) \(\left(x+1\right)\cdot\left(y-2\right)=0\)
b) \(\left(x+4\right)\cdot\left(y-2\right)=2\)
c) \(x\cdot y+5\cdot x+y=4\)
d) \(3\cdot x+4\cdot y-x\cdot y=15\)
Tìm số nguyên x:
a) \(x\cdot\left(x+3\right)=x\cdot\left(x+2\right)\)
b)\(x\cdot\left(2x+3\right)=x\cdot\left(x+1\right)\)
c) \(x\cdot\left(x-3\right)=2x-6\)
a) Tính
\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\cdot\cdot\left(1-\frac{1}{2014}\right)\cdot\left(1-\frac{1}{2015}\right)\cdot\left(1-\frac{1}{2016}\right)\)
b) Tìm x:
\(\frac{x-2}{12}+\frac{x-2}{20}+\frac{x-2}{30}+\frac{x-2}{42}+\frac{x-2}{56}+\frac{x-2}{72}=\frac{16}{9}\)
Tìm các so0os nguyên x,y biết:
\(\left(x^2+1\right)\cdot\left(x+1\right)=3^y\)
tìm x
a) \(\frac{x-1}{2}+\frac{x-2}{5}=\frac{1}{4}+\frac{x-7}{10}\)
b) \(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{1}{2x-3}-\frac{3}{2}\)
c)\(7\cdot\left(x-1\right)+2x\cdot\left(1-x\right)=0\)
d) \(\frac{x+1}{2008}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2009}+\frac{x+11}{2008}+\frac{x+12}{2007}\)
e) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}+\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}+\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Bài 1 : Tìm x;y biết :
\(x^2=y^2+2y+12\)
\(4x^2=y^2-2y=16\)
Bài 2 : Tìm n \(\in Z\)để biểu thức sau là phân số
a) \(\frac{3}{\left(n+1\right)\cdot\left(n-3\right)}\)
b) \(-\frac{4}{\left(n^2+1\right)\cdot\left(n+4\right)}\)
Tìm x,y thuộc Z, biết
\(\left(x-3\right)\cdot\left(y+x\right)=7\)
a)\(\left(2^2+3\right)\cdot\left(x-5\right)+14=5^2124:2^2\)
b) \(3^2\cdot\left(x+1\right)-3=2^3+7^2\cdot2:14\)
c) \(2^2\cdot3\cdot\left(x+5\right)-6=\left(2^3+2^2\right)\cdot2^2\)
d) \(\left(2^2+1\right)\cdot\left(x+14\right)=5^2\cdot4+\left(2^5+3^2+7^2\right):2\)
e) \(\left(2^2-1\right)\cdot\left(x-1\right)=2^2+\left(6^2+2^6\right):\left(5^2\cdot2\right)\)
g) \(\left(3^2-2\right)\cdot\left(x-12\right)+35=5^2+279:3^2\)
nhìn thì cảm thấy khó nhưng lại rất dễ đó
\(Tìm\)\(x,y\in N\)\(thỏa\)\(mãn\)
\(a.\)\(\left(3x-2\right)\cdot\left(2y-3\right)=1\)
\(b.\)\(\left(x+1\right)\cdot\left(2y-1\right)=12\)