Question

Tìm số nguyên x,y thỏa mãn:
a)3x(y+1)+y+1=7

#Tiếng anh lớp 6

Answer 1

\(a,3x\left(y+1\right)+\left(y+1\right)=7\\ =>\left(3x+1\right)\left(y+1\right)=7\)

\(+,TH1:\left\{{}\begin{matrix}3x+1=1\\y+1=7\end{matrix}\right.=>\left\{{}\begin{matrix}x=0\\y=6\end{matrix}\right.\\ +,TH2:\left\{{}\begin{matrix}3x+1=7\\y+1=1\end{matrix}\right.=>\left\{{}\begin{matrix}x=2\\y=0\end{matrix}\right.\\ +,TH3:\left\{{}\begin{matrix}3x+1=\left(-1\right)\\y+1=\left(-7\right)\end{matrix}\right.=>\left\{{}\begin{matrix}x=-\dfrac{2}{3}\\y=-8\end{matrix}\right.\\ +,TH4:\left\{{}\begin{matrix}3x+1=-7\\y+1=-1\end{matrix}\right.=>\left\{{}\begin{matrix}x=-\dfrac{8}{3}\\y=-2\end{matrix}\right.\)