\(\left(x+1\right)^2+\left(y-1\right)^2=0\)
\(\Rightarrow\left(x+1\right)^2=0\) và \(\left(y-1\right)^2=0\)
\(\Rightarrow x=-1\) và \(y=1\)
tíc mình nha
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tim cap so x,y nguyen biet :
a,\(|2x+3|+|2x-1|=\frac{8}{2|x-5|+2}\)
