Question

Tìm số nguyên x:

x+(x+1)+(x+2)+(x+3)+....+(x+13)+(x+14)=14

Answer 1

\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+14\right)=14\)

\(x+x+1+x+2+x+3+...+x+14=14\)

\(15x+\left(1+2+3+...+14\right)=14\)

\(15x+\frac{\left(14+1\right).14}{2}=14\)

\(15x+105=14\)

\(15x=-91\)

\(x=-\frac{91}{15}=-6,06\)

Answer 2

Ko chắc lắm

x+(x+1)+(x+2)+(x+3)+...+(x+13)+(x+14)=14

x+x+1+x+2+x+3+...+x+13+x+14=14

(x+x+x+x+...+x+x)+(1+2+3+...+14)=14

15x + 14 = 14

15x = 14 - 14

15x = 0

    x = 0:15

    x = 0

Vậy x=0

Answer 3

Hoàng hôn ( Cool Team )   bạn thông minh quá (1+2+3+4+...+14)=14