\(\frac{x}{4}-\frac{1}{y}=\frac{1}{2}=\frac{2}{4}\)
\(\Rightarrow\)\(\frac{1}{y}=\frac{x-2}{4}\)
\(\Rightarrow\)\(\left(x-2\right)y=4\)
Vậy ( x ; y ) = ( 1 ; -4 ) ; ( 0 ; -2 ) ; ( -2 ; -1 ) ; ( 6 ; 1 ) ; ( 4 ; 2 ) ; ( 3 ; 4 )
Theo đề ta có :
\(\frac{x}{4}-\frac{1}{y}=\frac{1}{2}=\frac{2}{4}\)
\(\Rightarrow\frac{x.y}{4.y}-\frac{4}{4.y}=\frac{2y}{4y}\)
\(\Rightarrow\frac{xy-4}{4y}=\frac{2y}{4y}\)
\(\Rightarrow xy-4=2y\)\(\Rightarrow xy-2y=4\Rightarrow y\left(x-2\right)=4\)
\(\Rightarrow y\left(x-2\right)=\left(-1\right).\left(-4\right)=\left(-2\right)\left(-2\right)=\left(-4\right)\left(-1\right)=1.4=2.2=4.1\)
nên ta có bảng sau :
x-2 | -1 | -2 | -4 | 1 | 2 | 4 |
x | 1 | 0 | -2 | 3 | 4 | 6 |
y | -4 | -2 | -1 | 4 | 2 | 1 |