=> \(2.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-...+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{16}{34}\)
=>\(2.\left(1-\frac{1}{x+2}\right)=\frac{16}{34}\)
=>\(1-\frac{1}{x+2}=\frac{4}{17}\)
=> \(\frac{1}{x+2}=\frac{13}{17}\)
=>\(x=-\frac{9}{13}\)