Question

Tìm số nguyên x, nếu biết:

       \(5^{2x+1}=125^{x+25}\)

ai nhanh mik tick cho 3 cái

Answer 1

\(5^{2x+1}=125^{x+25}\)

\(\Rightarrow5^{2x+1}=\left(5^3\right)^{x+25}\)

\(\Rightarrow5^{2x+1}=5^{3x+75}\)

\(\Rightarrow2x+1=3x+75\)

\(\Rightarrow3x-2x=1-75\)

\(\Rightarrow x=-74\)

Answer 2

\(5^{2x+1}=125^{x+25}\)

\(\Rightarrow5^{2x+1}=\left(5^3\right)^{x+25}\)

\(\Rightarrow5^{2x+1}=5^{3x+75}\)

\(\Rightarrow2x+1=3x+75\)

\(\Rightarrow-x=74\)

\(\Rightarrow x=-74\)

Answer 3

x=9 nha bn