Question

Tìm số nguyên x , biết:

\(\left|x-1\right|\le2\)

 

 

Answer 1

Ta có: \(\left|x-1\right|\le2\)

\(\Rightarrow\)\(\left|x-1\right|=0\)

         \(\left|x-1\right|=1\)

         \(\left|x-1\right|=2\)

\(\Rightarrow\)\(x-1=0\)

        \(x-1=-1\)

        \(x-1=1\)

        \(x-1=-2\)

        \(x-1=2\)

\(\Rightarrow\)\(x=1\)

        \(x=0\)

        \(x=2\)

        \(x=-1\)

        \(x=3\)

Answer 2

x e { 3; -1; 2; 0; 1}

Answer 3

\(\left|x-1\right|\le2\)

\(\Rightarrow-2\le x-1\le2\)

\(\Rightarrow-2+1\le x-1+1\le2+1\)

\(\Rightarrow-1\le x\le3\)

=> x = {-1 ; 0 ; 1 ; 2 ; 3}

Answer 4

X=0;1;2;3;(-1)k minh nha

Answer 5

x e { 3;-1;0;1;2}