\(4>x>-4\)
\(x=\left\{3;2;1;0;-1;-2;-3\right\}\)
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
k nhé
\(x\in\left\{\pm3;\pm2;\pm1;0\right\}\)
HTDT
\(4>x>-4\)
Mà x nguyên
=> \(x\in\left\{-3;-2;-1;0;1;2;3\right\}\)
Vậy ..........
Vì x là số nguyên
=> x thuộc{3;2;1;0;-1;-2;-3}
Ck hk tốt
\(x\in\left\{-3,-2,-1,0,1,2,3\right\}\)
~Hok tốt~
~~~Leo~~~
vì x là số nguyên,4>x>-4
=>x thuộc{-3,-2,-1,0,1,2,3}
VÌ x THUỘC SỐ NGUYÊN, NÊN:
X THUỘC {-3;-2;-1;0;1;2;3}
\(4>x>-4\)
\(x=\left\{3;2;1;0;-1;-2;-3\right\}\)
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
k nhé
Vì x là số nguyên
=> x thuộc{3;2;1;0;-1;-2;-3}
.............
ta có:
4>x>-4
=>x\(\in\){\(\pm\)1;\(\pm\)2;\(\pm\)3}
vậy x\(\in\){\(\pm\)1;\(\pm\)2;\(\pm\)3}