Question

Tìm số nguyên x biết:(3x-3)³=26+1²⁰¹⁸

Answer 1

(3x-3)³=26+1²⁰¹⁸

(3x-3)³=26+1

(3x-3)³=27

=>(3x-3)³=3³

=>3x-3=3

=>3x=6

=>x=2

Answer 2

\(\left(3x-3\right)^3=26+1^{2018}\)
\(\Rightarrow\left(3x-3\right)^3=26+1\)
\(\Rightarrow\left(3x-3\right)^3=27=3^3\)
\(\Rightarrow3x-3=3\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
Vậy \(x=2\)

Answer 3

(3x-3)³=26+1²⁰¹⁸

(3x-3)³=26+1

(3x-3)³=27

(3x-3)³=3³

3x-3=3

3x=6

x=6:3

x=2

Answer 4

(3x−3)3=26+12018

⇒(3x−3)3=26+1

⇒(3x−3)3=27=33

⇒3x−3=3

⇒3x=6

⇒x=2

Vậy x=2