Ta có: \(\frac{2x-9}{240}=\frac{39}{80}=\frac{117}{240}\)
=>\(2x-9=117\)
\(2x=117+9=126\)
\(x=126:2=63\)
Ta có :\(\frac{39}{80}=\frac{117}{240}\)
nên \(\frac{2x-9}{240}=\frac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(2x=117+9\)
\(2x=126\)
\(x=126:2\)
\(x=63\)