Question

tìm số nguyên x biết rằng 3x+8 chia hết cho x-1

Answer 1

= 0,4 nha !

Answer 2

3x+8 divisible by x-1

=> 3x-3+11 divisible by x-1

Because 3x-3 divisible by x-1

=> 11 divisible by x-1

=> x-1 =-1;-11;1;11

=> x=0;-10;2;12

Thus x=0;-10;2;12.

Answer 3

\(3x+8⋮x-1\Rightarrow3\left(x-1\right)+11⋮x-1\)

\(\Rightarrow11⋮x-1\Rightarrow x-1\inƯ\left(11\right)=\left\{\pm1;\pm11\right\}\)

\(\Rightarrow x\in\left\{2;0;12;-10\right\}\)

Vậy....................