Question

Tìm số nguyên x, biết: \(\frac{2}{x+32} = \frac{-1}{3x+5}\)

Answer 1

Ta có:

\(\frac{2}{x+32}=\frac{-1}{3x+5}\)

\(\Leftrightarrow2\left(3x+5\right)=-1\left(x+32\right)\)

\(\Leftrightarrow6x+10=-x-32\)

\(\Leftrightarrow7x=-42\)

\(\Rightarrow x=-6\)

Vậy................

hok tốt

Answer 2

\(\frac{2}{x+32}=\frac{-1}{3x+5}\)

\(\Rightarrow\frac{2}{x+32}=\frac{2}{-6x-10}\)

\(\Rightarrow x+32=-6x-10\)

\(x+6x=-10+32\)

\(\Rightarrow7x=22\Rightarrow x=\frac{22}{7}\)

Answer 3

\(\frac{2}{x+32}=\frac{-1}{3x+5}\)

\(\Rightarrow2\left(3x+5\right)=-1\left(x+32\right)\)

\(\Rightarrow6x+10=-x-32\)

\(\Rightarrow6x+x=-32-10\)

\(\Rightarrow7x=-42\)

\(\Rightarrow x=-42:7\)

\(\Rightarrow x=-6\)

Answer 4

Ta có: \(\frac{2}{x+32}=\frac{-1}{3x+5}\)

\(\Rightarrow\frac{2}{x+32}=\frac{2}{-6x-10}\)

\(\Rightarrow x+32=-6x-10\)

\(\Rightarrow x+6x=-10+32\)

\(\Rightarrow7x=22\)

\(\Rightarrow x=\frac{22}{7}\)

Vậy \(x=\frac{22}{7}\)

Answer 5

\(\Rightarrow2.\left(3x+5\right)=-1.\left(x+32\right)\)

\(\Rightarrow6x+10=-x-32\)\(\Rightarrow42=-7x\Rightarrow x=-6\)

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