a)\(\text{ 4x - 15 = -75 - x}\)
\(4x-15+75+x=0\)
\(5x+60=0\)
\(5x=-60\)
\(x=-14\)
Vậy....
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Học tốt
b)\(|2x-7|+2=13\)
\(|2x-7|=11\)
\(\Leftrightarrow\hept{\begin{cases}2x-7=11\\2x-7=-11\end{cases}\Leftrightarrow\hept{\begin{cases}2x=18\\2x=4\end{cases}\Leftrightarrow}\hept{\begin{cases}x=9\\x=2\end{cases}}}\)
vậy x=9 hoặc x=2
a) 4x - 15 = -75 - x
4x + x = -75 + 15
5x = -60
x= -60:5
x=-12
b) |2x - 7| + 2 = 13
| 2x - 7 | = 11
th1: 2x-7= 11
2x = 18
x = 9
th2: 2x - 7 = -11
2x = -4
x = -2
c)(2x - 1)^2 = 9
(2x-1)^2= 3^2
2x-1 = 3
2x = 4
x = 2
d)2x (x - 3) = 0
Th1: 2x=0
x= 0
Th2: x- 3 =0
x= 3
Hok tốt!!!
a) 4x - 15=-75 - x
4x-15+75+x=0
5x+60=0
5(x+12)=0
<=>x=-12
vay x=-12
b) |2x-7|+2=13
|2x+7|=11
\(\Leftrightarrow\orbr{\begin{cases}2x+7=11\\2x+7=-11\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-9\end{cases}}}\)
vay x=2 hoac x=-9
c) \(\left(2x-1\right)^2=9\Leftrightarrow2x-1=3\)
\(2x=4\Rightarrow x=2\)
vay x=2
d) \(2x\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}}\)
vay x=0 hoac x=3
a) 4x - 15 = -75 - x
4x + x = -75 + 15
5x = -60
x = (-60) : 5
x = -12.
b, \(|2x-7|+2=13\)
\(|2x-7|\) = 13 - 2
\(|2x-7|\) = 11
\(\Rightarrow\orbr{\begin{cases}2x-7=11\\2x-7=-11\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x=18\\2x=-4\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=9\\x=-2\end{cases}}\)
c, \(\left(2x-1\right)^2\)= 9
\(\Rightarrow\orbr{\begin{cases}\left(2x-1\right)^2\\\left(2x-1\right)^2\end{cases}}\)=
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