Question

tìm số nguyên x biết:        

32-2 (x+1)=42                    24-6(2x + 1)=6

12-5 (x+2)=32                    132-2(x-1)=32

14-5 (x+4)=9.                      92-7(x+3)=15

 

Answer 1

a , 32 - 2 ( x + 1 ) = 42

2 ( x + 1 ) = 32 - 42

2 ( x + 1 ) = -10

x + 1 = -10 : 2 = -5

x = -5 - 1 = -6

b, 12 - 5 (x + 2 ) = 32

5 ( x + 2 ) = 12 - 32 = -20

x + 2 = -20 : 5 = -4

x = -4 - 2 = -6

Answer 2

c , 14 - 5 ( x + 4 ) = 9

5 ( x + 4 ) = 14 - 9

5 ( x + 4 ) = 5

x + 4 = 5 : 5 = 1

x = 1 - 4 = -3

d , 24 - 6 ( 2x + 1 ) = 6

6 ( 2x + 1 ) = 24 - 6

6 ( 2x + 1 ) = 18

2x + 1 = 18 : 6

2x + 1 = 3

2x = 3 - 1 = 2

x = 2 : 2 = 1

Answer 3

e , 132 - 2 ( x - 1 ) = 32

2 ( x - 1 ) = 132 - 32

2 ( x- 1 ) =100

x - 1 = 100 : 2 = 50

x = 50 + 1 = 51

f , 92 - 7 ( x + 3 ) = 15

7 ( x + 3 ) = 92 - 15 = 77

x + 3 = 77 : 7 = 11

x = 11 - 3 = 8