Question

tìm sô nguyên x 

a)\(\dfrac{2x}{-9}\)= \(\dfrac{10}{91}\)

Answer 1

`a)[2x]/[-9]=10/91`

`=>2x.91=10.(-9)`

`=>182x=-90`

`=>x=-90/182`

`=>x=-45/91`

Answer 2

\(\Rightarrow2x\times91=10\times\left(-9\right)\\ \Rightarrow2x=\dfrac{-90}{91}\\ \Rightarrow x=\dfrac{-90}{91}:2\\ \Rightarrow x=-\dfrac{45}{91}\)

Answer 3

\(\dfrac{2x}{-9}=\dfrac{10}{91}\)

\(\Rightarrow2x.91=-9.10\)

\(\Rightarrow182x=-90\)

\(\Rightarrow x=-90:182\)

\(\Rightarrow x=-\dfrac{45}{91}\)

Answer 4

⇒2x×91=10×(−9)⇒2x=91−90​⇒x=91−90​:2⇒x=−9145​