<=> \(\frac{3^{3n}}{3^n}=9\)<=> \(3^{2n}=3^2\)<=>n=1
\(27^n\div3^n=9\)
\(\Rightarrow3^{3n}\div3^n=9\)
\(\Rightarrow3^{3n-n}=9\)
\(\Rightarrow3^{2n}=3^2\)
\(\Rightarrow2n=2\)
\(\Leftrightarrow n=1\)
Vậy muốn 27^n : 3^n = 9 thì n=1
27^n:3^n=9
(3^3)^n:3^n=3^2
3^3n:3^n=3^2
3^3n-n=3^2
3^2n=3^2
=> 2n=2
n=2:2
n=1
Vậy n=1
\(27^n:3^n=9\)
\(\Rightarrow\left(27:3\right)^n=9\)
\(\Rightarrow9^n=9\)
\(\Rightarrow9^n=9^1\)
\(\Rightarrow n=1\)
Vậy n = 1
_Chúc bạn học tốt_
