\(2n-1⋮n-1\)
\(\Rightarrow2n-2+1⋮n-1\)
\(\Rightarrow2\left(n-1\right)+1⋮n-1\)
\(\Rightarrow1⋮n-1\)
\(\Rightarrow n-1\inƯ\left(1\right)\)
\(\Rightarrow n-1\in\left\{-1;1\right\}\)
\(\Rightarrow n\in\left\{0;2\right\}\)
\(2n-1=2n-2+1=2\left(n-1\right)+1\)
Vì \(2\left(n-1\right)⋮n-1\)\(\Rightarrow\)Để \(2n-1⋮n-1\)thì \(1⋮n-1\)
\(\Rightarrow n-1\inƯ\left(1\right)=\pm1\)\(\Rightarrow n\in\left\{0;2\right\}\)
Vậy \(n\in\left\{0;2\right\}\)
