to nham so nguyen N biet n-4 lchia het n-1
Ta có : \(n-4⋮n-1\)
\(\left(n-1\right)-3⋮n-1\)
\(\Rightarrow3⋮n-1\Leftrightarrow n-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
n-1 | -3 | -1 | 1 | 3 |
n | -1 | 0 | 2 | 4 |
Vậy \(n\in\left\{-1;0;2;4\right\}\)
to nham so nguyen N biet n-4 lchia het n-1
Ta có : \(n-4⋮n-1\)
\(\left(n-1\right)-3⋮n-1\)
\(\Rightarrow3⋮n-1\Leftrightarrow n-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
n-1 | -3 | -1 | 1 | 3 |
n | -1 | 0 | 2 | 4 |
Vậy \(n\in\left\{-1;0;2;4\right\}\)
tim so hoan chinh n biet khi phan tich ra thua so nguyen to n=2p;n=22p;n=24p .ma p la so nguyen to lon hon 2
tim n la so tu nhien biet:
A=(n-2).(n2+n-1) la so nguyen to
cho bieu thuc B=4/n-3 voi n la so nguyen
a, so nguyen n phai co dieu kien gi de B la phan so
b, Tim so B biet n=0;n=10;n=-2
THANKS NHIU
bai 1 tim so tu nhien co 4 chu so ab cd biet abcd+abc+ab+a=4321.tim abcd
bai 2 cho m , n la cac so tu nhien va p la so nguyen to thoa man 9/m-1=m+n/p. tinh A= p^2-n
bai 3 tim so co 3 chu so biet abc 1000/a+b+c=abc.
Biet rang 3n cong 1 va 5n cong 4 (n thuoc N ) la 2 so khong nguyen to cung nhau . Tim UCLN cua 2 so tren
tim x thuoc N biet 97.x la so nguyen to ( . la dau nhan)
cho A=n-1/n-4
tim n nguyen de A la mot phan so
tim n nguyen de n la mot so nguyen
1. Cho Phan so B=\(\frac{n}{n-4}\)(voi n \(\in\)Z)
a. Tim So nguyen n de B la Phan so
b. Tim so Nguyen n de B co Gia tri la so tu nhien
2. Tim cac so nguyen x, y biet
a.\(\frac{x}{-3}=\frac{4}{y}\)
b. \(\frac{2}{x}=\frac{y}{-9}\)
Cho A= n-1/n+4
a) Tim n nguyen de A la mot phan so
b) Tim n nguyen de A la mot so nguyen