Ta có :\(b=\left(a+b+c+d\right)-\left(a+c+d\right)\)
\(\Rightarrow b=1-2=-1\)
\(c=\left(a+b+c+d\right)-\left(a+b+d\right)\)
\(\Rightarrow c=1-3=-2\)
\(d=\left(a+b+c+d\right)-\left(a+b+c\right)\)
\(\Rightarrow d=1-4=-3\)
Ta có :\(a+b+c+d=1\)
\(\Rightarrow a-1-2-3=1\)
\(\Rightarrow a-6=1\)
\(\Rightarrow a=7\)
Vậy \(a=7;b=-1;c=-2;d=-3\)