Các câu hỏi tương tự
Tìm x : \(\frac{x+4}{2007}+\frac{x+3}{2008}=\frac{x+2}{2009}+\frac{x+1}{2010}\)
1,Tìm số hữu tỉ x biết\(\frac{x+4}{2005}+\frac{x+3}{2006}=\frac{x+2}{2007}+\frac{x+1}{2008}\)
2,tìm x biết:\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)
Tìm X biết: \(\frac{x+3}{2007}-\frac{x+3}{2008}=\frac{x+3}{2010}+\frac{x+3}{2009}\)
Tìm x biết :
a, \(\frac{x+5}{2010}+\frac{x+6}{2009}+\frac{x+7}{2008}=-3\)
b, \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+349}{5}=0\)
tìm x,biết:\(\frac{x+1}{2009}+\frac{x+2}{2008}=\frac{x+3}{2007}+\frac{x+4}{2006}\)
tìm x biết:\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
\(\frac{x+6}{2010}\)+\(\frac{x+5}{2009}\)=\(\frac{x+4}{2008}\)+\(\frac{x+3}{2007}\).Hãy tìm x....
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Tìm x biết:
1) \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2) \(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
tìm x biết:
\(\frac{x-1}{2011}+\frac{x-2}{2010}+\frac{x-3}{2009}=\frac{x-4}{2008}\)