mk mới lớp 6
hổng bt làm đâu
\(\sqrt{2\sqrt{3}-3}=\sqrt{3x\sqrt{3}}-\sqrt{y\sqrt{3}}\)
\(\Rightarrow2\sqrt{3}-3=\left(3x+y\right)\sqrt{3}-6\sqrt{xy}\)
\(\Rightarrow\hept{\begin{cases}3x+y=2\\xy=\frac{1}{4}\end{cases}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{6}\\y=\frac{3}{2}\end{cases}}};\hept{\begin{cases}x=\frac{1}{2}\\y=\frac{1}{2}\end{cases}}\).