\(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\left(-\dfrac{3.3-10.2}{6}\right)=\dfrac{2}{5}\\ -\dfrac{2}{3}x-\dfrac{3}{5}=\dfrac{2}{5}:\left(-\dfrac{29}{6}\right)\\ -\dfrac{2}{3}x-\dfrac{3}{5}=-\dfrac{12}{145}\\ -\dfrac{2}{3}x=-\dfrac{12}{145}+\dfrac{3}{5}\\ -\dfrac{2}{3}x=\dfrac{-12+3.29}{145}\\ -\dfrac{2}{3}x=\dfrac{15}{29}\\ x=-\dfrac{45}{58}\)