\(21A=14B=6C\Rightarrow\frac{A}{\frac{1}{21}}=\frac{B}{\frac{1}{14}}=\frac{C}{\frac{1}{6}}\)VÀ A+B+C=180
ADTCCDTSBN ta có
\(\frac{A}{\frac{1}{21}}=\frac{B}{\frac{1}{14}}=\frac{C}{\frac{1}{6}}=\frac{A+B+C}{\frac{1}{21}+\frac{1}{14}+\frac{1}{6}}=\frac{180}{\frac{2}{7}}=180:\frac{2}{7}=630\)
\(\Rightarrow\hept{\begin{cases}21A=630\\14B=630\\6C=630\end{cases}}\Rightarrow\hept{\begin{cases}A=30\\B=45\\C=105\end{cases}}\)
mot banh xe rang cua co 24 rang(no quay duoc 80 vong tren 1 phut). No khop voi mot banh xe rang cua khac co x rang. Gia su banh xe rang cua thu 2 quay dc y vong trong 1 phut. Hay bieu dien y theo x
