tim so co 4 chu so co dang abcd biet rang abc+acc+dbc=bcc
Tim so co bon chu so co dang abcd , biet rang abc+acc+dbc=bcc
tim so co 4 chu so abcd, biet rang abd la so chinh phuong, neu cong them 72 don vi thi duoc mot so chinh phuong
Tim so co bon chu so dang abcd biet rang abcd+ abc+ab+a= 4321
tim mot so chan co hai chu so , biet rang chu so hang chuc ga 4 lan chu so hang don vi ?
bai 13 :tim tich cua so nho nhat co ba chu so khac nhau voi so chan lon nhat co mot chu so.
bai 14 :tim mot so,biet rang neu giam so do di 5 lan sau do them 10 don vi thi duoc so le nho nhat co hai chu so.
bai 15 :tim mot so biet rang neu gap so do len 4 lan,duoc bao nhieu lai gap len 6 lan thi duoc 360
tim so co 5 chu so biet rang so do co rang abcba voi c / 2 < A<C VOI TONG CAC CHU SO BANG bb
Tim so co 4 chu so abcd(abcd co gach tren dau )biet abcd=(5c+1)^2
tim so co 5 chu so .biet rang so do co rang abcba voi c/2 <a <c va tong cac chu so do bang bb