Question

Tìm số chưa biết

\(\frac{1}{2}a-\frac{3}{4}=\frac{5}{15}\)

\(1\frac{8}{15}-\frac{2}{3}=0.2\)

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=3-\frac{3}{4}\)

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Answer 1

\(\frac{1}{2}a-\frac{3}{4}=\frac{5}{15}\)

\(\Leftrightarrow\frac{1}{2}a-\frac{3}{4}=\frac{1}{3}\)

\(\Leftrightarrow\frac{1}{2}a=\frac{1}{3}+\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{2}a=\frac{4}{12}+\frac{9}{12}\)

\(\Leftrightarrow\frac{1}{2}a=\frac{13}{12}\)

\(\Leftrightarrow a=\frac{13}{12}\div\frac{1}{2}\)

\(\Leftrightarrow a=\frac{13}{12}\times\frac{2}{1}\)

\(\Leftrightarrow a=\frac{13}{6}\)

Answer 2

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=3-\frac{3}{4}\)

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{9}{4}\)

\(x+\frac{1}{8}=\frac{9}{4}.\frac{2}{3}\)

\(x+\frac{1}{8}=\frac{3}{2}\)

\(x=\frac{3}{2}-\frac{1}{8}\)

\(x=\frac{11}{8}\)

Vậy \(x=\frac{11}{8}\)

Answer 3

\(1\frac{8}{15}-\frac{2}{3}=0,2\)

\(\Leftrightarrow\frac{23}{15}a-\frac{2}{3}=\frac{1}{5}\)

\(\Leftrightarrow\frac{23}{15}a=\frac{1}{5}+\frac{2}{3}\)

\(\Leftrightarrow\frac{23}{15}a=\frac{3}{15}+\frac{10}{15}\)

\(\Leftrightarrow\frac{23}{15}a=\frac{13}{15}\)

\(\Leftrightarrow a=\frac{13}{15}\div\frac{23}{15}\)

\(\Leftrightarrow a=\frac{13}{23}\)

Answer 4

\(\left(x+\frac{1}{8}\right)\div\frac{2}{3}=3-\frac{3}{4}\)

\(\Leftrightarrow\left(x+\frac{1}{8}\right)\div\frac{2}{3}=\frac{12}{4}-\frac{3}{4}\)

\(\Leftrightarrow\left(x+\frac{1}{8}\right)\div\frac{2}{3}=\frac{9}{4}\)

\(\Leftrightarrow x+\frac{1}{8}=\frac{9}{4}.\frac{2}{3}\)

\(\Leftrightarrow x+\frac{1}{8}=\frac{9}{6}\)

\(\Leftrightarrow x+\frac{3}{24}=\frac{36}{24}\)

\(\Leftrightarrow x=\frac{36}{24}-\frac{3}{24}\)

\(\Leftrightarrow x=\frac{33}{24}=\frac{11}{8}\)

Answer 5

\(\frac{1}{2}a-\frac{3}{4}=\frac{5}{15}\)

\(\frac{1}{2}a-\frac{3}{4}=\frac{1}{3}\)

\(\frac{1}{2}a=\frac{1}{3}+\frac{3}{4}\)

\(\frac{1}{2}a=\frac{4}{12}+\frac{9}{12}\)

\(\frac{1}{2}a=\frac{13}{12}\)

\(a=\frac{13}{12}:\frac{1}{2}\)

\(a=\frac{13}{12}.2\)

\(a=\frac{13}{6}\)

Vậy\(a=\frac{13}{6}\)

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=3-\frac{3}{4}\)

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{12}{4}-\frac{3}{4}\)

\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{9}{4}\)

\(x+\frac{1}{8}=\frac{9}{4}\times\frac{2}{3}\)

\(x+\frac{1}{8}=\frac{3}{2}\)

\(x=\frac{3}{2}-\frac{1}{8}\)

\(x=\frac{12}{8}-\frac{1}{8}\)

\(x=\frac{11}{8}\)

Vậy\(x=\frac{11}{8}\)

Câu thứ 2 e chưa cho số cần tìm nha e