\(pt\Rightarrow x=\frac{11-3y}{2}=5-y+\frac{1-y}{2}\)
Do \(x\in Z\) nên \(\frac{1-y}{2}\in Z\)
Đặt \(\frac{1-y}{2}=t\in Z\Rightarrow y=1-2t\)
\(\Rightarrow x=5-\left(1-2t\right)+t=3t+4\)
Vậy \(\left(x;y\right)=\left(3t+4;1-2t\right)\text{ với }t\in Z.\)