Question

Tìm nghiệm của đa thức:

M(x)=x³-25x

M(x)=x⁵+27x²

G(x)=(x²+2)(-2x+4)

Answer 1

cho M(x) =0

\(=>x^3-25x=0=>x\left(x^2-25\right)=0\)

\(=>\left[{}\begin{matrix}x=0\\x^2-25=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x^2=25=>\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\end{matrix}\right.\)

Answer 2

M(x) =0

\(=>x^5+27x^2=0=>x^2\left(x^3+27\right)=0\)

\(=>\left[{}\begin{matrix}x^2=0\\x^3=-27\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Answer 3

M(x)=x³-25x=x.(x²-25)=x.(x-5)(x+5)