\(x^2-2x=0\)
\(\Leftrightarrow x\cdot\left(x-2\right)=0\Rightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
x*(x-2)
TH1)
x=0
TH2)
x-2=0
x=2
Vậy x=0 hoặc x=2
x^2 - 2x = 0
Suy ra x . ( x - 2 ) = 0
Suy ra x = 0
x - 2 = 0
x = 2